Question

18 years ago, a woman was three times as old as her daughter Now, the woman is twice as old as her daughter. The sum of the present ages of the <eman and her daughter is
18 ਸਾਲ ਪਹਿਲਾਂ ਇੱਕ ਔਰਤ ਦੀ ਉਮਰ ਆਪਣੀ ਧੀ ਨਾਲੋਂ ਤਿੰਨ ਗੁਣਾਂ ਜ਼ਿਆਦਾ ਸੀ। ਹੁਣ ਉਹ ਔਰਤ ਆਪਣੀ ਧੀ
ਨਾਲੋਂ ਦੁਗਣੀ ਉਮਰ ਦੀ ਹੈ। ਉਸ ਔਰਤ ਅਤੇ ਉਸਦੀ ਧੀ ਦੀ ਉਮਰ ਦਾ ਜੋੜ ਕੀ ਹੈ ?
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Answer 1

Answer:

let 18yr ago age of son is x than father's

age is 3x

after 18 years( present)

father's age = 3x +18

son's age = x + 18 according to question father is twice as

old as his son

than

3x+18=2(x+18)

3x+18=2x+36

3x-2x=36-18

x=18

present age of father = 3x+18 put the value of x. =3x18+18 =72

present age of son = x+18=18+18= 36 sum of present ages of father and son =

72+36=108

Step-by-step explanation:

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