Chemistry, asked by rajamanak1984, 1 year ago

180 mL of pure water (d = 1 g/mL) is saturated with NH3 gas. If the solution contains 40% by mass of NH3 and has a density 0.9g/mL The volume of NH3 solution is​

Answers

Answered by bhagyashreechowdhury
0

Answer:

The volume of water = 180 ml

Density of water = 1 g/ml

We know,  

Density = Mass / Volume

Mass of water = 180 * 1 = 180 g ….. (i)

Let the volume of the NH₃ solution be “V” ml.

Here, the density of the solution is given as 0.9 g/ml

Mass of the solution = 0.9 * V

 

Also, we are given that the solution contains 40% by mass of NH₃, therefore,  

Mass of water will be = 60% of the mass of solution = (60/100)*0.9V ….. (ii)

Comparing eq. (i) & (ii), we get

180 = (60/100) * 0.9 V

⇒ 180 = 0.6*0.9 V

⇒ 180 = 0.54 V

⇒ V = 180/0.54 = 333.33 ml

Thus the volume of NH₃ solution is 333.33 ml .

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