180 students appeared in an entrance test which has 2 different sections,namely english and maths.80 students cleared both sections and 90 students cleared math section but not english.how many students cleared english section but not maths.assume that no one failed in both the sections
Answers
Answer:10
Step-by-step explanation:
total no. of students =180
passed in both =90
passed in math =80
passed in English =
180-90+80
= 100-90
= 10
hope it helps you....
Answer: 10
Step-by-step explanation:
Given,
- 180 students appeared in 2 different exams, English and Maths.
- 90 Students passed only in Maths.
- 80 Students passed in both English and Maths.
To Find: The number of students who passed only in English.
Explanation:
- Since mentioned that no one failed in both sections, all the 180 students can be grouped under three groups.
- Students who have passed in both subjects
- Students who have passed only in Mathematics
- Students who have passed only in English.
- That is, [(Students who have passed in both subjects) +
(Students who have passed only in Mathematics) +
(Students who have passed only in English)]
= Total number of students.
- Let us assume that the number of students who have passed only in English is "x".
- As per the data provided in the question statement,
- Therefore, 10 students passed only in English.
In a class of 75 students, 10 play only cricket, 15 play only football, 30 play basketball, 8 play only cricket & football, 4 play only cricket & basketball & 4 play all the three sports. How many students do not play any of the three games?
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In an examination, questions were asked in five sections. Out of the total students, 5% candidates cleared the cut-off in all the sections and 5% cleared none. Of the rest, 25% cleared only one section and 20% cleared four sections. If 24.5% of the entire candidates cleared two sections and 300 candidates cleared three sections. Find out how many candidates appeared at the examination?
A.1000
B.1200
C.1500
D.2000
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