Question

18a^3b^2+36ab^4-24a^2b^3- factorise​

Answer 1

Answer

6ab²(3a²+6b²-4ab)

Answer 2

The factorized expression is $6ab^2(3(a^2+2b^2)-4ab)$

Therefore $18a^3b^2+36ab^4-24a^2b^3=6ab^2(3(a^2+2b^2)-4ab)$

Step-by-step explanation:

Given expression is $18a^3b^2+36ab^4-24a^2b^3$

To factorize the given expression :

$18a^3b^2+36ab^4-24a^2b^3$

$=6ab^2(3a^2+6b^2-4ab)$  ( here taking common term $6ab^2$ outside the terms )

$=6ab^2(3(a^2+2b^2)-4ab)$

Therefore $18a^3b^2+36ab^4-24a^2b^3=6ab^2(3(a^2+2b^2)-4ab)$