18a²-50, Factorise it using appropriate identities.
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Solution :
Given 18a² - 50
= 2( 9a² - 25 )
= 2 [ ( 3a )² - 5² ]
= 2( 3a + 5 )( 3a -5 )
[ Since , x² - y² = ( x + y )( x - y ) ]
••••
Therefore ,
18
Given 18a² - 50
= 2( 9a² - 25 )
= 2 [ ( 3a )² - 5² ]
= 2( 3a + 5 )( 3a -5 )
[ Since , x² - y² = ( x + y )( x - y ) ]
••••
Therefore ,
18
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