A wheel rotating at a speed of 600 rpm (revolutions per minute) about its axis is brought to rest by applying a constant torque for 10 seconds. Find the angular deceleration and the angular velocity 5 seconds after the application of the torque. ?
Answers
Answered by
56
Given in the question :-
Rotation of the wheel(Initial) = 600 rpm or = 10 revolution / second
Final velocity = 0
Time = 10 second
now we have to find = ?
We know the formula ,
put all the values in the given formula
0 = 10 - α × 10
α = 1 revolution /second ²
Now the angular velocity at time change t = 5 sec.
ω'' = 10 - 1 × 5
ω'' = 5 revolution/second.
Hope it Helps :-)
Answered by
17
» Initial angular velocity of the wheel :-
____________________________
» After 10 sec final angular velocity of the wheel :-
=> v = 0
__________
So
__________________________
Now,
=> t = 5 sec
_________
» We know that :-
___________________[ANSWER]
======================================
_-_-_-_☆☆_-_-_-_
____________________________
» After 10 sec final angular velocity of the wheel :-
=> v = 0
__________
So
__________________________
Now,
=> t = 5 sec
_________
» We know that :-
___________________[ANSWER]
======================================
_-_-_-_☆☆_-_-_-_
Deepsbhargav:
theku Dimpy
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