Question

18g of glucose is dissolved in 90g of water .then the relatively lowering of vapour pressure of solution is

Answer 1

Answer: 1/51

Explanation:

Answer 2

Answer:

The correct answer is $0.0196 \sim 0.02$.

Explanation:

The molecular mass of a substance exists defined as the totality of the atomic masses of all the atoms present in a molecule of a substance.

The molecular formula exists for the expression of the number of atoms of each element in one molecule of a compound. The molecular formula description exists as the formula indicating the exact number of each atom in a molecule.

The molecular mass of water $=2 \times 1+1 \times 16$

$=18 \mathrm{~g}$

For $90 \mathrm{~g}$ $178.2 \mathrm{~g}$ water $\mathrm{n}_{\mathrm{A}}=5$

The molecular mass of glucose $6 \times 12+12 \times 1+6 \times 16=180 \mathrm{~g}$

For $18 g$ glucose $n_{B}=0.1$

Now,

$\mathrm{X}_{\mathrm{B}}=\frac{0.1}{0.1+5}$

$=0.0196 \sim 0.02$

Therefore, the correct answer is $0.0196 \sim 0.02$.

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