Question

HEYA .......


in a given fig. ABC is a quadrant of the circle of radius 28cm and the semicircle is drawn with BC as a diameter find the area of the shaded region .

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Answer 1

BC2=AC2+AB2
BC=28√2
ar of semicircle=1/2 πr2
1/2 ×22/7 ×14√2×14√2
=616
area of quadrant=1/4 πr2
1/4 ×22/7 ×28√2×28√2
=616
area of triangle= 1/2 p×b
1/2×28×28
=392
area of shaded region is
392+616-616
=392