Question

18g of glucose is present in 1000g of an aqueous solution of glucose

Answer 1

Explanation:

18 g of glucose → 18/180 mole or 0.1 mole of glucose. Here, 0.1 mole of glucose present in 1000 g of solvent. On the basis of known definition i.e. molality, so, the concentration of the glucose in the solvent would be 0.1 molal or simply 0.1 m.

Answer 2

Answer:

18 g of glucose → 18/180 mole or 0.1 mole of glucose. Here, 0.1 mole of glucose present in 1000 g of solvent. On the basis of known definition i.e. molality, so, the concentration of the glucose in the solvent would be 0.1 molal or simply 0.1 m.