Math, asked by janakiaadhinenij, 6 months ago

19) 5 Two barrels contain a mixture of ethanol and gasoline. The content of the ethanol is
60% in the first barrel and 30% in the second barrel. In what ratio must the mixtures from the
first and the second barrels be taken to form a mixture containing 50% ethanol?
(b) 2:1
(c) 2:3
(d) 3:2
(e) None of these
(a) 1:2​

Answers

Answered by princemaurya462k
0

Step-by-step explanation:

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Answered by HA7SH
20

Step-by-step explanation:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 \huge\bold\star\red{\underline{Answer:-}}

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 \Large\bold\star\green{\underline{Explanation:-}}

\Longrightarrow Let they are required to be taken in 1 : x

\Longrightarrow Then according to the question:-

\Longrightarrow 1×6+x×3=(x+1)5

\Longrightarrow Solving we get x = \frac{1}{2}

\Longrightarrow So ratio of first to second = 2 : 1

\Longrightarrow So the correct option is (b) 2 : 1

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 \bold\star\purple{\underline{That's\ all}}\star

 \bold\star\orange{\underline{Hope\ it\ helps\ you}}\star

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