Question

19.6 MH2SO4=_____ NH2SO4 ??

Answer 1

Answer:see H2SO4 is a DIBASIC acid, so normality will be twice of molaritiy, hence it will be(19.6*2)=39.2 normal H2SO4

Explanation:

Answer 2

Answer: 19.6 M $H_2SO_4$= 39.2N $H_2SO_4$

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n= moles of solute

$V_s$ = volume of solution in L

Given : 19.6 M $H_2SO_4$

19.6 moles of $H_2SO_4$ in 1 Liter of solution

mass of $H_2SO_4=moles\times {\text {Molar mass}}=19.6\times 98=1920.8g$

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

$Normality=\frac{\text{no of gram equivalents}}{\text{Volume in L}}$

$Normality=\frac{\text{given mass}}{\text {Equivalent mass}\times {\text{Volume in L}}}$

Equivalent weight is calculated by dividing the molecular weight by n factor.  

${\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}$

n= basicity for acids  , For $H_2SO_4$ , n =2

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

As $H_2SO_4$ dissociates to give 2 $H^+$ and thus it has basicity of 2.

${\text{Equivalent weight}}=\frac{98}{2}=49g$

$\text{no of gram equivalents of}H_2SO_4=\frac{1920.8}{49}=39.2gramequivalents$

$Normality=\frac{39.2}{1L}=39.2N$

Thus Normality will be 39.2.