Question

19.7kg of gold was recovered from smuggler.The number of atoms of gold recovered are:(Au=197)

Answer 1

Explanation:

given mass , m =19.7 kg

N= no. of atoms

A= avogadro no.

molar mass , M= 197

m/M=N/A

19.7/197 =N/6.022×10^23

0.1×6.022×10^23 = 6.022×10^22 atoms

u can also convert kg into gram