Question

(19) A body is released from the top of a
building of height 19.6 m. Find the velocity
with which the body hits the ground.​

Answer 1

Answer:19.6 ms^-1

Step-by-step explanation:

v^2=u^2 + 2gh

→ v^2= 0+ 2*9.8*19.6

→v^2 = 19.6^2

→v=19.6