Question

19. A wooden block of mass 400 g is placed on a plane glass plate. If the coefficient of friction between the glass and wood is 0.15, what minimum force is needed just to slide the block? (g = 9.8 ms 2) (Hint: F = umg] (Ans. 0-588 N​

Answer 1

Answer:

Data:

mass of wooden block=m=400g = 400/1000 = 0.4kg

coefficient of Friction=u=0.15

force=F=?

Solution:

F=umg

F= 0.15×0.4×9.8

F=0.588N