Question

19 cot
1- Sino 1- Sina
1+ sinx-1- sinx
ve (0.5
2
im
$​

Answer 1

Answer:

We have,

⇒cot

−1

(

1−sinx

−

1+sinx

1−sinx

+

1+sinx

)

⇒cot

−1

(

(1−sinx)−(1+sinx)

(

1−sinx

+

1+sinx

)

2

)

⇒cot

−1

(

1−sinx−1−sinx

1−sinx+1+sinx+2

1−sin

2

x

)

⇒cot

−1

(

−2sinx

2+2

cos

2

x

)

⇒cot

−1

(

−sinx

1+cosx

)

⇒cot

−1

⎝

⎛

−2sin

2

x

cos

2

x

1+2cos

2

x/2−1

⎠

⎞

⇒cot

−1

(

sinx/2

cosx/2

)

⇒cot

−1

(−cotx/2)

⇒cot

−1

(cot(π−x/2))

⇒π−x/2.

Step-by-step explanation:

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