Question

19) Find a
point on the
on the y-oscis which is
celuidistant from the paint'l 5; 4) and (-2, 1)​

Answer 1

Step-by-step explanation:

Let the point on y-axis be (0,y).

By, Distance formula we have,

D=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

Therefore,

(4)

2

+(y−3)

2

=

(−6)

2

+(y−5)

2

16+y

2

+9−6y=36+y

2

+25−10y

25−6y=61−10y

4y=36

y=9

Hence, the required point is (0,9).

Answer 2

Let P(0,y) be any point on y-axis.

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PB

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0)

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y)

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0)

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y)

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y) 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y) 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y) 2 25+4+y

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y) 2 25+4+y 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y) 2 25+4+y 2 +4y=9+4+y

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y) 2 25+4+y 2 +4y=9+4+y 2

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y) 2 25+4+y 2 +4y=9+4+y 2 −4y

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y) 2 25+4+y 2 +4y=9+4+y 2 −4y8y=−16

Let P(0,y) be any point on y-axis.Let A(5,−2) and B(−3,2). Then,PA=PBPA 2 =PB 2 (5−0) 2 +(−2−y) 2 =(−3−0) 2 +(2−y) 2 25+4+y 2 +4y=9+4+y 2 −4y8y=−16y=−2