Question

19 Find the least number by which 72 should be multiplied to make it a
perfect cube​

Answer 1

$72=2^3\times 3^2$

We need to make the exponents multiple of 3, so that it becomes a perfect cube.

prime factor 2

The number 3 is already already a multiple of 3.

prime factor 3

The least number 1 should be added to 2, to make it a multiple of 3.

So the number is 3 with exponent of 1. (3¹ = 3)

The number is 3.

( $72\times 3=6^3$, true )