Question

19. Find the least number of square tiles required to pave the ceiling of a room 15 m 17 cm long and 9 m 2 cm broad.​

Answer 1

Answer:

814 tiles are required

Step-by-step explanation:

Length of room= 15m17cm= 1500+17= 1517cm

Breadth of room=9m2cm= 900+2=902cm

HCF of 1517 and 902 is 41.

Thus, area of each tile (41×41)= 1681sq.cm

Hence, req. no. of tiles = 1517×902/1681 = 814

Hope it helps!