Question

19. Find the roots of the following quadratic equation:
2√3x^2 – 5x + √3 = 0​

Answer 1

2√3 x2 – 5x + √3 = 0

Compare given equation with the general form of quadratic equation, which is ax2 + bx + c = 0

a = 2√3, b = – 5 , c = √3

D = b2 – 4ac

= (– 5)2 – 4 x 2√3 x √3

= 25 – 24

= 1 > 0

Roots of equation are real.

Answer 2

Answer:

2√3x^2-5x-√3=0

2√3x^2-6x+x-√3=0

2√3x(x-√3)+1(x-√3)=0

(x-√3) (2√3x+1)=0

either, x-√3=0

x=√3

or, 2√3x+1=0

x=-1/2√3