Question

19) Find the value of sec? 10°-cot-80° +
sin 15°cos 75° +cos 15° sin 75°
cos sin (90° - 0) + sin cos (90°-0)​

Answer 1

Answer:

solved

Step-by-step explanation:

sec 10°-cot-80° +

sin 15°cos 75° +cos 15° sin 75°

sin (90° - 0) + sin cos (90°-0) = v

v = sec 10°-cot-80° + sin 15°cos 75° +cos 15° sin 75° sin (90° - 0) + sin cos (90°-0)

v = sec 10°-cot-80° + sin 15°cos 75° +cos 15° sin 75°  sin 90°  + sin cos 90°

v = sec 10°-cot-80° + sin 15°cos 75° +cos 15° sin 75° cos 0°  + sin 0°

v = sec 10°-cot-80° + sin 15°cos 75° +cos 15° sin 75°

v = sec 10°-cot-80° + sin 90°

v = sec 10°-cot-80° + 1

v =1 + sec 10°+ cot80°

v =1 + sec 10°+ tan10°