Question

19) Find the zeros of the polynomial x2 - 3 and verify the relationship between the zeroes and
the coefficients​

Answer 1

Answer:

total is 0

multiple is -3

Step-by-step explanation:

${x}^{2} - 3 \\ (x + \sqrt{3} )(x - \sqrt{3} ) \\ x = \sqrt{3} \: \: \: \: and \: \: \: x = - \sqrt{3} \\ \alpha = \sqrt{3} \: \: \: \: \beta = - \sqrt{3} \\ \\ total \: of \: zeroes \: is \: \\ \alpha + \beta = \frac{ - b}{a} = \sqrt{3} + ( - \sqrt{3} ) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{3} - \sqrt{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0 \\ \\ multiple \: of \: zeroes \: is \\ \alpha \beta = \frac{c}{a} = \sqrt{3} \times - \sqrt{3} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 3$

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