19. Five resistors, each of 3 ohm are connected as shown
in Fig 8.50. Calculate the resistance (a) between the
points P and Q, and (b) between the points X and Y.
322
232
302
322
302
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Answered by
3
Explanation:
Where are points X and Y?
To simplify,
PQ has 2 resistors of 3 ohm connected in series, the resultant of which is connected in parallel to another 3 ohm resistor.
R net = R1 + R2 in a series
=> R net = 3 + 3
= 6 ohms
Now we have this 6 ohm resistor connected in parallel with a 3 ohm resistor.
R net = [ 1/R1 + 1/R2 ]^-1
= [ 1/6 + 1/3 ]^-1
2 ohms
Hence the resistance between points P and Q is 2 ohms.
Assuming that the points X and Y are including the other 2 resistances of 3 ohms each,
the resistors 3 ohms 2 ohms and 3 ohms are in series
Hence the total resultant resistance ( bet. X and Y) = 2 + 3 + 3
= 8 ohms
Answered by
0
Answer:
0.4
Explanation:
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