Physics, asked by zaid4771, 1 year ago

19. Four particles of mass 1kg, 2kg, 3kg and 4kg are placed at the four vertices a, b, c and d of square of side 1m. Find the position of centre of mass of the particle

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Answered by Anonymous
0
Let ABC be the triangle.

Let mass m be situated at the midpoint of side BC.

It experiences equal and opposite force due to particle at B and C

Hence the total force experienced by the mass is only due to A

Which equal to Gm^2/(a×sqrt(3)/4))^2

4Gm^2/3a^2
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