19 gm mixture of Na2CO3 and NaHCO3 on heating gives 2.2 gm CO2 gas. Find % NaHCO3 by mass in mixture.
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Answer:
2NaHCO
3
Δ
Na
2
CO
3
+H
2
O+CO
2
1.12 L CO
2
at STP corresponds to
22.4L/mol
1.12L
=0.05 moles.
0.05 moles of CO
2
will come from 2×0.05=0.1 mole of NaHCO
3
.
The molar mass of NaHCO
3
is 84 g/mol. Mass of 0.1 moles of NaHCO
3
=84×0.1=8.4g
Mass of Na
2
CO
3
=19−8.4=10.6g
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