19) * In a triangle HIJ, angle H = 30°. If I(HI) = l(IJ) = 12, find the length of HJ.
Answers
Answered by
6
Answer:
HJ = 12√3
Step-by-step explanation:
in Δ HIJ
HI = IJ
=> ∠H = ∠J
∠H = 30°
=> ∠J = 30°
in Δ HIJ
∠H + ∠I + ∠J = 180°
=> 30° + ∠I + 30° = 180°
=> ∠I = 120°
HI = IJ = 12
HJ² = HI² + IJ² - 2(HI)(IJ)Cos∠I
=> HJ² = 12² + 12² - 2(12)(12)Cos120°
=> HJ² = 2 *12² (1 - Cos120°)
=> HJ² = 2 *12² (1 - (-0.5))
=> HJ² = 2 *12² (1.5)
=> HJ² = 3 *12²
=> HJ = 12√3
Answered by
0
Answer:
Answer is 12√3 as explained in picture
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