Question

19) * In a triangle HIJ, angle H = 30°. If I(HI) = l(IJ) = 12, find the length of HJ.​

Answer 1

Answer:

HJ = 12√3

Step-by-step explanation:

in Δ HIJ

HI = IJ

=> ∠H = ∠J

∠H = 30°

=> ∠J = 30°

in Δ HIJ

∠H + ∠I + ∠J = 180°

=> 30° + ∠I + 30° = 180°

=> ∠I = 120°

HI = IJ = 12

HJ² = HI² + IJ²  - 2(HI)(IJ)Cos∠I

=> HJ² = 12² + 12² - 2(12)(12)Cos120°

=> HJ² = 2 *12² (1  - Cos120°)

=> HJ² = 2 *12² (1  - (-0.5))

=> HJ² = 2 *12² (1.5)

=>  HJ² = 3 *12²

=> HJ = 12√3

Answer 2

Answer:

Answer is 12√3 as explained in picture