19. In the adjoining figure, DC = AE = BE, AB || DC. Show that
a. SADE = ACED
b. AECB E ACED
c. AADE = AECB
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Answered by
0
Answer:
Step-by-step explanation:
IN THE ADJACENT FIGURE
DECF IS ARECTANGLE SO DE=CF⇒1
AS,DC||Ab,AB IS A TRANSVERSALSO ANGLE AED=ANGLEBFC⇒2GIVEN AD=BC⇒3
FROM1,2,3
BY RHS congruency
triangleAED=TRIangleDFC
BY CPCT
AE = BF
Answered by
8
Answer:
AB || DC.
DE is the transversal
a. ADE=CED(alternate interior angles)
AB || DC.
CE is the transversal
b. ECB=CED(alternate interior angles)
I hope my answer helps you☺☺
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