Question

19. sec A (1 - sin A) (sec A + tan A) = 1​

Answer 1

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Answer 2

Answer:

(secA-secAsinA)(secA+tanA)=1

secA=1/cosA

so,(secA-tanA)(secA+tanA)=1

using, a^2 -b^2=(a-b)(a+b)

sec^2 A-tan^2 A=1

as

,sec^2 A=1+ tan^2A