Question

19. Solve for x:
4(4x -- 1) - 2 (2x - 1+x)= 1 (2x + 8)
9 3 3 9

Answer 1

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Answer 2

Answer:

Answer:4(4x-1) - 2 (2x-1+x)=1(2x+8)

Answer:4(4x-1) - 2 (2x-1+x)=1(2x+8)4(4x-1)-2(2x-1+x)=10x

Answer:4(4x-1) - 2 (2x-1+x)=1(2x+8)4(4x-1)-2(2x-1+x)=10x16x-1 - 4x - 1 +x =10x

Answer:4(4x-1) - 2 (2x-1+x)=1(2x+8)4(4x-1)-2(2x-1+x)=10x16x-1 - 4x - 1 +x =10x15x - 4x,x is 2= 10x

Answer:4(4x-1) - 2 (2x-1+x)=1(2x+8)4(4x-1)-2(2x-1+x)=10x16x-1 - 4x - 1 +x =10x15x - 4x,x is 2= 10x11x = 10x

Answer:4(4x-1) - 2 (2x-1+x)=1(2x+8)4(4x-1)-2(2x-1+x)=10x16x-1 - 4x - 1 +x =10x15x - 4x,x is 2= 10x11x = 10x2x=11-10

Answer:4(4x-1) - 2 (2x-1+x)=1(2x+8)4(4x-1)-2(2x-1+x)=10x16x-1 - 4x - 1 +x =10x15x - 4x,x is 2= 10x11x = 10x2x=11-102x = 1

Answer:4(4x-1) - 2 (2x-1+x)=1(2x+8)4(4x-1)-2(2x-1+x)=10x16x-1 - 4x - 1 +x =10x15x - 4x,x is 2= 10x11x = 10x2x=11-102x = 1x = 1/2