Question

19. Solve using formula : x2-2x-8=0.​

Answer 1

Answer:

x^2-2x-8=0

$x ^{2} - 2x - 8 \\ x ^{2} + (2x - 4x) - 8 \\ x ^{2} + 2x - 4x - 8 \\ x (x + 2) - 4(x + 2) \\ \\(x - 4)(x + 2)$

Answer 2

Answer:

x2-2x=8

x2-2x-8=0

sum = -2

product = -8

• no; s = -4,2

Step-by-step explanation:

x2-4x+2x-8=0

x[x-4]+2[x-4]=0

[x-4] [x+2[x-4]=0

[x-4] [x+2]=0

x-4=0

x=4

x+2=0

x=0