Question

19. The area of an isosceles triangle
having base as 4cm and length of
one of the equal sides is 6 cm is​

Answer 1

Answer:

( 1 )so if we have to find permeter

so P=a +b+c

p=4+6+6

p=16, 4^2

Step-by-step explanation:

( 2 ) If we have to SIDE AD

so in tri. ABC. create a meadian at B to c

so by Pythagoras theorem

in tri. ABD AD^2=AB^2+BD^2

AD^2=6^2+2^2

AD^2=36+4

AD^2=40

AD=√40

AD=4√10

( 3 )NOW area tri. ABC

semi permeter

=a/2+b/2+c/2

so=6/2+4/2+6/2

=3+2+3

=8

area will be

√8(8-6)(8-4)(8-6)

√8×2×4×2

2×2×2√2

area of tri. ABC=8√2

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HOW TO FIND area, meadian,permeter