Question

19. the diagonal of a quadrilateral shaped is 24 cm and perpendicular dropped on it from the reminding opposite vectiors are 6 cm and 12 CM find the area of field​

Answer 1

Answer:

Area of quadrilateral =1/2 ×d×(length of perpendicular)

1/2×24×18

216cm^2

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Answer 2

Given,

• The Diagonal of a Quadrilateral shaped is 24 cm
• Perpendicular drooped on it the reminding opposite vector are 6 cm and 12 cm.

To Find,

• Area of Quadrilateral Shaped Field

Solution :

$\implies$ We Know that :

$\boxed{\sf{\pink{Area \ of \ Quadrilateral = \dfrac{1}{2} \times Diagonal \times (a + b)}}}$

Here,

• Diagonal - 24 cm
• a  - 6 cm
• b - 12 cm

$\mapsto \underline{\sf{Now, Put \ the \ Values}}$

$\implies \sf{\dfrac{1}{2} \times 24 \times (6 + 12)}$

$\implies \sf{\dfrac{1}{2} \times 24 \times 18}$

$\implies \sf{12 \times 18}$

$\implies \boxed{\sf{\red{216 \ cm^{2}}}}$

Therefore,

$\boxed{\large{\bold{Area \ of \ Field = 216 \ cm^{2}}}}$

$\rule{200}2$