19) The diagram below shows a hydraulic machine in which the area of
cross – section of the pistons A and B are 10 m
and 750m' and the pressure acting on piston A is 25 Pa. What is the
force on the piston B?
Answers
Answered by
2
Answer:
F1*A1 =F2*A2
10*25=750x X
x=0.333
Explanation:
inbox me, bcz there might a problem in question, I am not sure that 25 pas or force, if it's pascal, then answer should be 1875 pascal on piston b and 2.5 Newton per m^2 force.
Answered by
2
Explanation:
In a hydraulic machine, the both cross sectional areas are connected with a pipe, which means, that the same amount of force is generated on the both sides as the same amount of liquid is displaced.
Therefore, Force at the side A = Force at the side B
Pressure at A × Area of A = Force at the side B
10×25= F(B)
F(B) = 250N
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