Question

19. The HCF of two numbers is 3 and their LCM is 36.
If one of the numbers is 12, what is the other?​

Answer 1

Answer:

HCF(a,b) × LCM(a,b) = product of 'a' and 'b'.

Given one number is 12

Let the other number be 'a'.

HCF(a,12) = 3

LCM(a,12) = 36

12 × a = 36 × 3

a = 36 × 3 ÷ 12 = 9.

Step-by-step explanation:

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