Physics, asked by kusumchawla1000, 1 year ago

19. The variation of pressure P with volume V for an
ideal monatomic gas during an adiabatic process
is shown in figure. At point A the magnitude of rate
of change of pressure with volume is​

Attachments:

Answers

Answered by JAYADADI
3

Answer:

PLEASE MARK ME AS BRAIN LIST PLEASE

This is an upright parabola, so the equation is P = kV  2

 By Ideal gas equation,

P = nRT /V

So, nRT /V = kV  2

nRT = kV  3

By first law,

dQ = dU + PdV

Let the heat capacity of the gas in this process be C, dQ = nC dT

for diatomic gas, C v =5R /2

C= C v =5 R /2+C v  = R/3 =  Cv  = 17R /6

Similar questions