Math, asked by bajajpriyanka, 1 day ago

19. There is a road in the shape of a
circular ring (annulus) around a circular
garden and outside it. If the difference
of the outer circumference and the inner
circumference of the road is 88 m, find
the width of the road.​

Answers

Answered by ak6204828788
16

Answer:

2piR - 2pir = 88

2pi(R - r) = 88

R - r = 88×7/44

R - r = 14

so the width of road is 14 meter

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