Question

19) Tickets numbered from 1 to 20 are mixed up together and then a ticket is drown at
random. What is the probability that the ticket has a number which is a multiple of 3
or 7.​

Answer 1

Step-by-step explanation:

All multiple of 3 and 7 bunder 20= 3,6,9,12,15,18,7,14

Probability = Fav. outcome/Total outcome

=8/20

=2/5

Answer 2

Answer:

P(E)=2/5

Step-by-step explanation:

multiples of 3&7= 3,6,9,12,15,18,7,14

no.of.possible outcome=8

P(E)=8/20=2/5

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