Physics, asked by yogesh474, 9 months ago

19. Uniformly charged rod of length L carrying charge q is kept on y-axis with its center at
origin. Electric field at x =
is-
V2kq
(A) 2kqi
() 2/2kq (i+j)
(D) 242k9 (i – j)
12​

Answers

Answered by rathodmaheshdh2000
1

Answer:

Explanation:

So what you do is say that for an element of rod with a tiny length dℓ and charge QLdℓ located at 0,z,θ (where θ is actually moot since ρ=0),

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