Question

1a3 (b3-c3) + b3 (c3-a3) +c3(a3-b3)​

Answer 1

Answer:

0

Step-by-step explanation:

3a(3b-3c)+3b(3c-3a)+3c(3a-3b)

=3ab-3ac+3bc-3ba+3ca-3cb

=0

Answer 2

${ \huge{ \color{pink}{ \underline{ \underline{ \sf{ \color{aqua}{คຖŞຟēr}}}}}}}$

a3(b3-c3)+b3(c3-a3)+c3(a3-b3)

ab9-ac9+bc9-ba9+ca9-cb9

Collect the like terms:-

ab9-ba9-ac9+ca9+bc9-cb9

Postive and negative terms will cut each other.

$\sf \cancel{ab9} + \cancel{ba9} - \cancel{ac9} + \cancel{ca9} + \cancel{bc9} - \cancel{ca9} = 0$

${\large { \color{aqua} {\boxed{ \color{pink}{\sf {❥Hope \: it \: helps \: you....}}}}}}$