1g of hcl and 1g of naoh are mixed together in 1 litre water.the nature of the resulting solution will be
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HCl + NaOH = NaCl + H2O
Molar mass of HCl = 1 + 35.5 = 36.5
Molar mass of NaOH = 23 + 16 + 1 = 40
If 36.5 g HCl require 40g NaOH
1 g HCl will require = (1 x 40)/36.5 = 1.1 g
But we have only 1 g of NaOH
This means the 1 g of NaOH will all be consumed and some HCl will remain unreacted
The resulting solution will be acidic due to excess HCl
Molar mass of HCl = 1 + 35.5 = 36.5
Molar mass of NaOH = 23 + 16 + 1 = 40
If 36.5 g HCl require 40g NaOH
1 g HCl will require = (1 x 40)/36.5 = 1.1 g
But we have only 1 g of NaOH
This means the 1 g of NaOH will all be consumed and some HCl will remain unreacted
The resulting solution will be acidic due to excess HCl
Answered by
1
Answer:
Explanation:
HCl + NaOH = NaCl + H2O
Molar mass of HCl = 1 + 35.5 = 36.5
Molar mass of NaOH = 23 + 16 + 1 = 40
If 36.5 g HCl require 40g NaOH
1 g HCl will require = (1 x 40)/36.5 = 1.1 g
But we have only 1 g of NaOH
This means the 1 g of NaOH will all be consumed and some HCl will remain unreacted
The resulting solution will be acidic due to excess HCl
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