Question

1gm of H2 at S.T.P occupies 11.2 litre.The volume occupied by 3gm of H2 at 300k and 0.7m of Hg will be

Answer 1

Given:

1 gm of H2 at STP occupies 11.2 litres.

To find:

Volume occupied by 3 gm H2 at 300 K and 0.7 m Hg head.

Calculation:

$760 \: mm \:Hg \: \equiv \: 1 \: atm$

$= > 700 \: mm \: Hg \equiv \dfrac{700}{760} \times 1 \: atm$

$= > 700 \: mm \: Hg \equiv 0.92 \: atm$

In the 1st case:

$PV = \dfrac{W}{m}RT$

$= > 1 \times 11.2 = \dfrac{1}{m}R \times 298$

In the 2nd case:

$PV = \dfrac{W}{m}RT$

$= > 0.92 \times V = \dfrac{3}{m}R \times 300$

Dividing the two equations:

$= > \dfrac{0.92 \times V}{11.2} = \dfrac{3 \times 300}{298}$

$= > \dfrac{0.92 \times V}{11.2} = 3.02$

$= > 0.92 \times V = 33.82$

$= > V = 36.76 \: litres$

So , final answer is :

$\boxed{ \red{ \large{ \bold{ V = 36.76 \: litres}}}}$

Answer 2

Answer:

Explanation: dicchi