If the density of methanol is 0.793 kg/L, what is its volume needed for making 20 grams of solution?
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Weight of Methanol required to prepare 2500 ml.of 0.25M Solution
= 2.5 x Mole.Wt x 0.25 g.
Molecular weight of Methanol= 32
So Weight of Methanol required= 2.5 x 32 x 0.25= 20 g.
Volume of Methanol required =20/0.793= 25.22 ml.
So on diluting 25.22 ml.of Methanol with distilled water and then making up the Solution to 2500 ml, will give you 0.25M , Solution of Methanol.
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