Question

1In a right-angled AABC, right-angled at B,

if the ratio of AB to AC is 1:/2, then find

the values of

i) 2tan A /
1- tan^2 A

and
ii) 2tan A /1+ tan^2A
​

Answer 1

Answer:

AB : AC = 1 : 2⇒ACAB=21 

∴ AB = x and AC = 2x, for some x.

By Pythagoras theorem, we have

AC2=AB2+BC2

⇒(2x)2=x2+BC2

⇒BC2=2x2−x2=x2

⇒BC=x

∴tanA=ABBC=xx=1

we have,

1+tan2AtanA=1+121=21

Step-by-step explanation:

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