Question

1mol of any gas at STP has a volume of 22.4L

calculate the mass of 112 L S-32 O-16 present at STP​

Answer 1

Answer: 160g & 80g

Explanation: 1 mole of any gas at STP has a volume of 22.4L.

So we have here 112 L.

Therefore no: of moles we have = $\frac{Given volume}{Volume in STP}$ =112L/22.4L = 5moles

We know,

           Moles = Mass/Molar mass

           Mass = Moles × Molar mass

Therefore,

         Mass of S = 5 × 32 = 160g

         Mass of O = 5 × 16 = 80g