Question

A partical travel 1st half distance with uniform speed of 40m/s and next half distance with uniform speed of 80m/s calculate average speed

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Answer 1

Answer:

lєt thє tσtαl díѕtαncє вє d.

ín thє fírѕt pαrt σf jσurnєч, pαrtíclє trαvєlѕ díѕtαncє 2d wíth ѕpєєd 6m/ѕ, ѕσ cσrrєѕpσndíng tímє.

t1=62d=12dѕ

thє tímєѕ σf ѕєcσnd αnd thírd pαrtѕ σf thє jσurnєч αrє єquαl t2=t3. thє ѕum σf díѕtαncєѕ σf thєѕє

pαrtѕ αrє 2d lєt thє díѕtαncє σf thє ѕєcσnd pαrt σf thє jσurnєч вє х. thєn

t2=t3→2х=42d−х→х=6dm,

t2=26d=12d=t3

tσtαl tímє σf jσurnєч:

t=t1+t2+t3=312d=4dѕ

αvєrαgє ѕpєєd: 

v=td=4m/ѕ

Step-by-step explanation:

l hope it will help u ☺️✌️☺️

Answer 2

Assume the distance as lcm of 40 and 60

Assume the distance as lcm of 40 and 60240 total distance=240

Assume the distance as lcm of 40 and 60240 total distance=240Time taken in first half=120/40=3

Assume the distance as lcm of 40 and 60240 total distance=240Time taken in first half=120/40=3Second half=120/60=2

Assume the distance as lcm of 40 and 60240 total distance=240Time taken in first half=120/40=3Second half=120/60=2Avg speed=total distance/total time taken

Assume the distance as lcm of 40 and 60240 total distance=240Time taken in first half=120/40=3Second half=120/60=2Avg speed=total distance/total time taken=240/5=48

thanks for your thanks but pls I don't need I was just in brainly for frnds

ab frnds hi nahi rahe toh Kya karu Mai brainly Mai

Kal ya parso leaving.... ☹☹

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