Math, asked by gprasanna0604, 8 months ago

1Q)Factories the following:-

1)6x^2-x-2=0
2)3x^2-2✓6+2=0
3)2x^2+x-300=0
4)2x^2-5x+3=0.....

Please answer it neatly, with step by step.​

Answers

Answered by hardik747
1

Answer:

6{x}^{2}  -x - 2 = 0 \\ 6 {x}^{2} - 4x + 3x - 2  = 0\\ 2x(3x - 2) + 1(3x - 2)  = 0\\ (2x + 1)(3x - 2) = 0 \\ 2x + 1 = 0 \:  \:  \:  \:  \:  \:  \:  \: 3x - 2 = 0\\ x =   -  \frac{1}{2} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x =  \frac{2}{3}

3 {x}^{2}  - 2 \sqrt{6}   +  2 = 0

3 {x}^{2}  = 2 \sqrt{6}   -  2

  {x}^{2}  = \frac{2 \sqrt{6} - 2 }{3}

x =  \sqrt{ \frac{2 \sqrt{6 } - 2 }{3} }

2 {x}^{2}   + x  -  300 = 0

2 {x}^{2}  + 25x - 24x - 300 = 0

x(2x + 25) - 12(2x + 25) = 0

(x - 12)(2x + 25) = 0

x - 12 = 0 \:  \:  \:  \:  \:  \:  \:  \: \:  \:   2x + 25 = 0 \\ x = 12 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 2x =  - 25 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x =  \frac{ - 25}{2}

4 is homework for you

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