Question

1st line is obtained when transission from (n+1) energy is minimum and wavelength is maximum ? it's a right?​

Answer 1

Number of spectral lines obtained due to transition of electron from n

th

orbit to lower orbit N=

2

n(n−1)

And for maximum wavelength, the difference between the orbits of the series should be minimum.

Number of spectral lines N=

2

n(n−1)

=6

⇒

2

n(n−1)

=6

⇒n

2

−n−12=0

⇒(n−4)(n+3)=0

n=4

Now as the first line of the series has the maximum wavelength, therefore, electrons jump from the 4

th

orbit to 3

rd

orbit.