1st TERM OF AN AP IS 'a' AND 18th TERM IS 'b'.WHAT IS THE 10th TERM
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Hey !!!
1st term of an Ap is is a
t1 = a --------1)
t18 = b
let the first term of an Ap is a'
•°• tn = a' + (n - 1 ) d
t18 = a'+ (18- 1) d
t18 = a' + 17d
b = a' + 17d ---------2)
substracting equation 1 from 2
t18 - t1 = a' + 17d - a'
b - a = 17d
b - a /17 = d
Here we got first term = a
d = b - a /17
n = 10
hence , t10 = a + 9d
t10 = a + 9×(b-a/17)
t10 = 17a + 9b - 9a
t10 = 8a + 9b Answer ✔
____________________________
Hope it helps you !!!
@Rajukumar111
1st term of an Ap is is a
t1 = a --------1)
t18 = b
let the first term of an Ap is a'
•°• tn = a' + (n - 1 ) d
t18 = a'+ (18- 1) d
t18 = a' + 17d
b = a' + 17d ---------2)
substracting equation 1 from 2
t18 - t1 = a' + 17d - a'
b - a = 17d
b - a /17 = d
Here we got first term = a
d = b - a /17
n = 10
hence , t10 = a + 9d
t10 = a + 9×(b-a/17)
t10 = 17a + 9b - 9a
t10 = 8a + 9b Answer ✔
____________________________
Hope it helps you !!!
@Rajukumar111
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