Question

1T
(v) tan 2 tan
1
7
+ = 0
5 4) 17
금​

Answer 1

Answer:

$\bf \purple{i \: \: think \:the \: question \: is}$

$tan(2 {tan}^{ - 1} \frac{1}{5} - \frac{\pi}{4} ) + \frac{7}{17} = 0$

$\fbox \pink{answer:-}$

$= ( {tan}^{ - 1} ( \frac{ \frac{2 \times 1}{5} }{1 - \frac{1}{25} } ) - \frac{\pi}{4} ) + \frac{7}{17} \\ \\ = (tan( {tan}^{ - 1} \frac{ \frac{2}{5} }{ \frac{24}{25} } - \frac{\pi}{4} )) + \frac{7}{17} \\ \\ = \tan( {tan}^{ - 1} ) ( \frac{2 \times 5}{25} - \frac{\pi}{4} ) + \frac{7}{17} \\ \\ = \frac{tan \times {tan}^{ - 1} \frac{10}{24} - tan \frac{\pi}{4} }{1 - tan \times {tan}^{ - 1} \frac{10}{24} \times tan \frac{\pi}{4} } + \frac{7}{17} \\ \\ = \frac{ \frac{10}{24} - 1 }{1 + \frac{10}{24} \times 1 } + \frac{7}{17} \\ \\ = \frac{ \frac{10 - 24}{24} }{ \frac{24 + 10}{24} } + \frac{7}{17} \\ \\ = \frac{ - 14}{34} + \frac{7}{17} = 0$