Question

1uc and -2uc charge place distance 2cm and on 1cm p charge find the intensity at point p

Answer 1

Let

(x,y,z) - (3,2,5)

(x',y'z') = (0,-4,3)

Electric field is given as

E  = kq/r2

Here,

q = 1 μC = 10-6 C

r2 = dx2 + dy2 + dz2 =  [(3-0)2 + (2 - (-4))2 + (5-3)2]

or

r2 = 49m2

so,

E = (9x109 x 10-6) / 49