1x) If a compound, on analysis was found
to contain C = 18.5% 4 = 1.55%
I=55.04% and 0 = 24.8 7. then.
its empirical formula is
(a) Ch₂ocl(6) C5H10O5
(c) СНСlО (d) clch2o
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The answer will be (c) CHCIO
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